L16 Impulse & Momentum  脉冲和动量


HW10.43 -- 3 Ways to Solve: Energy & Springs

The circus has hired you to design a spring-launched roller coaster that will carry up to two passengers per car. The car goes up a 15-m-high hill, then descends 20 m to the track's lowest point. You've determined that the spring can be compressed a maximum of 2.0 m and that a loaded car will have a maximum mass of 400 kg . For safety reasons, the spring constant should be 20% larger than the minimum needed for the car to just make it over the top. (Note that all data is given to 2-sig figs) (a) What spring constant should you specify? (b) What is the maximum speed of a 350 kg car if the spring is compressed the full amount?
  1. Picture
  2. System & Assumptions
  3. Decision of solution method: Newton's Laws or Energy Method
  4. IF Newton; Free Body Diagram (including Fnet, show coordinate system)
  5. IF Energy: Before and After Diagram
  6. Solve
  7. Assess

Key Ideas

$$ \mathbf { \vec a } (t) = { { \mathbf { \vec F }(t) \over m } } \rightarrow \,$$ $$ \Delta \mathbf { \vec v } = \int { { \mathbf { \vec F }(t) \over m }\, dt } \,$$ $$ \Delta \mathbf { \vec p } = \int { { \mathbf { \vec F }(t) }\, dt } \equiv \mathbf { \vec J } \, $$

Momentum is based on Newton's 2nd and 3rd Laws (not new physics)



Advantage (優點): Simplifies solutions when only final state required.



Disadvantage (缺點): Loose all time information



isolated system → Δ p = 0 (Momentum Conservation)



Impulse: Newton's 2nd Law in another form



PHeT Sim Introduction

Lecture Knight vs4 Chapter 11


Collision Lab
Collision Lab (Introduction to Inelastic Collisions)

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