Review: Capacitors ΔV = Q/C (finding equivalent capacitor: Q, ΔV don't change)
Key Points
Current Density
$$ { \vec J = \, n \, e \, \vec v_d \, = \, n \, e \, \left( { {e \tau} \over m} \vec E \right) \equiv \sigma \vec E \equiv {1 \over \rho} \vec E \, \,\, [Am^{-2}] }\\
$$
Ohm's Law
From Basic Physics with | Assumptions
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$$ I \equiv \iint \vec J \cdot d \vec A = {1 \over \rho} \iint \vec E \cdot d \vec A $$
| ρ≠f(x,y,z) → drift velocity linearly (only) depends on E-field (τ = C)
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$$ I = {1 \over \rho} \iint \vec E \cdot d \vec A = {1 \over \rho} \vec E \cdot \iint d \vec A $$
| E is constant across the conductor cross section
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$$ I = {1 \over \rho} \vec E \cdot \vec A = {1 \over \rho} {\Delta V \over L} A $$
| E is ⊥ to conductor cross section. E is constant along wire.
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$$
\rightarrow I = {A \over {\rho L}} \Delta V \equiv {{\Delta V} \over R}\\
$$
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Kirchoff's Laws
1: Energy Conservation | $$ \Delta V_{closed \, loop} = \sum \Delta V_i = 0 \, \\$$
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2: Charge Conservation | $$ \sum I_{in} - \sum I_{out} = 0 \\$$
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Other
- Nonuniform Charge Distribution along surface of wire → longitudinal E-Field in wire → charge flow (current) in wire
- Battery is the source of everything: ℰ = W/q
→ ΔVbat = (1 - δ) ℰ (internal resistance)
→ Δ Vwire
→ Ewire = Δ Vwire/L
→ I = σ A Ewire = A/ρ Ewire
Magnitude of current is related to both battery's ℰ and wire's resistance: I = ΔVbat/Rwire
PBL Comments
Lecture Power Points: Current (J & I) and Resistance (R)
Knight Chapter 27